Question

the electron configuration of nitrogen (n) is
$1s^22s^22p^3$

$1s^22s^22p^4$

$1s^22s^22p^5$

$1s^22s^22p^6$

Explanation:

Nitrogen has an atomic number of 7, meaning it has 7 electrons. The electron configuration is built by filling orbitals: 1s holds 2, 2s holds 2, leaving 3 for 2p. So \(1s^2 2s^2 2p^3\) is correct. The other options have incorrect electron counts in the 2p orbital (4, 5, 6 electrons would correspond to different elements like oxygen, fluorine, neon, not nitrogen).

Answer:

A. \(1s^22s^22p^3\)