Question

the element bromine (br) has 7 valence electrons. which of the following elements would most readily form an ionic bond with bromine? (1 point) one atom of lithium, which has one valence electron one atom of carbon, which has 4 valence electrons one atom of magnesium, which has two valence electrons two atoms of neon, which has 8 valence electrons

Explanation:

To form an ionic bond, an element that donates electrons (metal, usually with 1, 2 valence electrons) and an element that accepts electrons (non - metal, like Br with 7 valence electrons) are needed. Bromine needs 1 electron to complete its octet. Lithium (Li) has 1 valence electron and is a metal. It can easily lose that 1 electron, and Br can gain it to form an ionic bond. Carbon (C) is a non - metal and forms covalent bonds more readily. Magnesium (Mg) has 2 valence electrons, and for Br to form an ionic bond with Mg, the electron transfer ratio would be different (2 Br atoms per Mg atom), while Li can form an ionic bond with Br in a 1:1 ratio more readily. Neon (Ne) is a noble gas with a full octet and does not form bonds easily.

Answer:

A. One atom of Lithium, which has one valence electron