Question

the end of a hose was resting on the ground, pointing up an angle. sal measured the path of the water coming out of the hose and found that it could be modeled using the equation $f(x)= - 0.3x^{2}+2x$, where $f(x)$ is the height of the path of the water above the ground, in feet, and $x$ is the horizontal distance of the path of the water from the end of the hose, in feet. when the water was 4 feet from the end of the hose, what was its height above the ground? 6.8 feet 4.8 feet 5.6 feet 3.2 feet

Explanation:

Step1: Identify the given values

We are given the function $f(x)= - 0.3x^{2}+2x$ and $x = 4$.

Step2: Substitute the value of x

Substitute $x = 4$ into the function: $f(4)=-0.3\times4^{2}+2\times4$.

Step3: Calculate the powers

First, calculate $4^{2}=16$. So $f(4)=-0.3\times16 + 2\times4$.

Step4: Perform multiplications

$-0.3\times16=-4.8$ and $2\times4 = 8$. Then $f(4)=-4.8 + 8$.

Step5: Calculate the sum

$f(4)=3.2$. So the height of the water above the ground when it is 4 feet from the end of the hose is 3.2 feet.

Answer:

B. 4.8 feet