Question

an engine with a normal rating of 900 hp has an emergency rating of 980 hp, what percentage of the normal rating is the emergency rating? (nearest whole number)
question 13 2 pts
if an engine develops 125 hp at 90% power, what hp would be developed at 75%? (nearest whole number)

Explanation:

Step1: Calculate percentage for first question

Let the normal rating be $a = 900$ and emergency rating be $b = 980$. The formula for percentage is $\frac{b}{a}\times100\%$. So, $\frac{980}{900}\times100\%=\frac{98000}{900}\% \approx 109\%$.

Step2: Calculate power for second question

If the engine develops 125 hp at 90% power, let the full - power be $x$. Then $0.9x = 125$, so $x=\frac{125}{0.9}$. To find the power at 75% power, we calculate $0.75\times\frac{125}{0.9}=\frac{0.75\times125}{0.9}=\frac{93.75}{0.9}\approx104$.

Answer:

109
104