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Question
enter the correct answer in the box.
what is the standard form of function f?
$f(x) = 4(x + 6)^2 + 5$
substitute numerical values into the equation for $a$, $b$, and $c$.
$f(x) = ax^2 + bx + c$
Step1: Expand the squared term
$(x+6)^2 = x^2 + 12x + 36$
Step2: Multiply by 4
$4(x^2 + 12x + 36) = 4x^2 + 48x + 144$
Step3: Add the constant term 5
$4x^2 + 48x + 144 + 5 = 4x^2 + 48x + 149$
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$f(x) = 4x^2 + 48x + 149$ (where $a=4$, $b=48$, $c=149$)