Question

entry ticket problems 1 problem problem 1/1 each large tick mark on the ruler represents 1 centimeter. what is the length of $overline{af}$ to the nearest $\frac{1}{2}$ of a centimeter? 0 1 2 3 4 5 6 7 8 submit > please double - check before submitting.

Explanation:

Step1: Identify start and end points

Point A is at 0 and point F is at 7.

Step2: Calculate the length

The length of $\overline{AF}$ is $7 - 0=7$ centimeters. Since we need to round to the nearest $\frac{1}{2}$ of a centimeter, 7 is already a whole - number and is closest to $7$ when considering halves.

Answer:

7