Question

for the equation $4x + 3y = 12$
a) complete the table:

x	y
0

b) plot the two points you found in the table.
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Explanation:

Step1: Solve for x when y=0

Substitute $y=0$ into $4x+3y=12$:
$4x + 3(0) = 12$
$4x = 12$
$x = \frac{12}{4} = 3$

Step2: Solve for y when x=0

Substitute $x=0$ into $4x+3y=12$:
$4(0) + 3y = 12$
$3y = 12$
$y = \frac{12}{3} = 4$

Step3: Identify points for plotting

The two points are $(3, 0)$ and $(0, 4)$. On the coordinate grid, $(3,0)$ is 3 units right on the x-axis, and $(0,4)$ is 4 units up on the y-axis.

Answer:

a) Completed table:

x	y
0	4

b) Plot the points $(3, 0)$ (on the positive x-axis, 3 units from the origin) and $(0, 4)$ (on the positive y-axis, 4 units from the origin) on the provided grid.