Question

equations involving fractions video 111 on www.corbettmaths.com question 5: solve the following equations (a) $\frac{3x + 5}{2}=7$ (b) $\frac{5x - 12}{3}=11$ (c) $\frac{4x + 2}{6}=5$ (d) $\frac{10x + 3}{4}=4$ (e) $\frac{5x - 8}{2}=10$ (f) $\frac{8x + 4}{5}=12.8$ (g) $\frac{2x + 13}{3}=1$ (h) $\frac{3x - 4}{7}=-4$ (i) $\frac{7x - 12}{3}=-25$ (j) $\frac{29 - 2x}{3}=5$ (k) $\frac{100 - 5x}{3}=30$ (l) $\frac{24 - 3x}{12}=5$

Explanation:

(a)

Step1: Multiply both sides by 2

$3x + 5=7\times2$
$3x + 5 = 14$

Step2: Subtract 5 from both sides

$3x=14 - 5$
$3x = 9$

Step3: Divide both sides by 3

$x=\frac{9}{3}$
$x = 3$

(b)

Step1: Multiply both sides by 3

$5x-12 = 11\times3$
$5x-12=33$

Step2: Add 12 to both sides

$5x=33 + 12$
$5x = 45$

Step3: Divide both sides by 5

$x=\frac{45}{5}$
$x = 9$

(c)

Step1: Multiply both sides by 6

$4x + 2=5\times6$
$4x + 2 = 30$

Step2: Subtract 2 from both sides

$4x=30 - 2$
$4x = 28$

Step3: Divide both sides by 4

$x=\frac{28}{4}$
$x = 7$

(d)

Answer:

$x = 3$