Question

evaluate the determinant.
$\begin{vmatrix} -2 & 15 \\ 4 & -6 end{vmatrix}$
$d = square$

Explanation:

Step1: Recall 2x2 determinant formula

For

$$\begin{vmatrix} a & b \\ c & d \end{vmatrix}$$

, determinant is $ad - bc$.

Step2: Substitute values into formula

$a=-2, b=15, c=4, d=-6$

$$\begin{align*} D &= (-2)(-6) - (15)(4) \end{align*}$$

Step3: Calculate each product

$$\begin{align*} (-2)(-6) &= 12, \quad (15)(4)=60 \end{align*}$$

Step4: Compute final difference

$$\begin{align*} D &= 12 - 60 \end{align*}$$

Answer:

$-48$