Question

a) evaluate each function at the specified value

1. $f(x) = 10x + 2 ; x = -8$
2. $f(x) = -x + 9 ; x = 7$

b) evaluate each function.

1. $f(x) = -(3x - 1) ; \text{find } f(-15)$
2. $f(x) = -6x - 12 ; \text{find } f(11)$

Explanation:

A) 1)

Step1: Substitute \( x = -8 \) into \( f(x) = 10x + 2 \)

\( f(-8) = 10\times(-8) + 2 \)

Step2: Calculate the result

\( 10\times(-8) = -80 \), then \( -80 + 2 = -78 \)

Step1: Substitute \( x = 7 \) into \( f(x) = -x + 9 \)

\( f(7) = -7 + 9 \)

Step2: Calculate the result

\( -7 + 9 = 2 \)

Step1: Substitute \( x = -15 \) into \( f(x) = -(3x - 1) \)

\( f(-15) = -(3\times(-15) - 1) \)

Step2: Simplify inside the parentheses first

\( 3\times(-15) = -45 \), then \( -45 - 1 = -46 \)

Step3: Apply the negative sign

\( -(-46) = 46 \)

Answer:

\( f(-8) = -78 \)

A) 2)