Question

evaluate the following functions.
you get unlimited reattempts.
$f(x) = -2x + 10$
$g(x) = -9x - 7$
find $f(-10) + g(10)$

Explanation:

Step1: Calculate \( f(-10) \)

Substitute \( x = -10 \) into \( f(x) = -2x + 10 \).
\( f(-10) = -2\times(-10) + 10 \)
\( f(-10) = 20 + 10 \)
\( f(-10) = 30 \)

Step2: Calculate \( g(10) \)

Substitute \( x = 10 \) into \( g(x) = -9x - 7 \).
\( g(10) = -9\times10 - 7 \)
\( g(10) = -90 - 7 \)
\( g(10) = -97 \)

Step3: Calculate \( f(-10) + g(10) \)

Add the results from Step1 and Step2.
\( f(-10) + g(10) = 30 + (-97) \)
\( f(-10) + g(10) = 30 - 97 \)
\( f(-10) + g(10) = -67 \)

Answer:

\(-67\)