evaluate the logarithmic expression: \$\\log_{16}(16)\$

$evaluate the logarithmic expression: \$\\log_{16}(16)\$$

evaluate the logarithmic expression: \$\log_{16}(16)\$

The logarithm $\log_b(a)$ is defined as the exponent $x$ such that $b^x = a$. So for $\log_{16}(16)$, we need to find $x$ where $16^x = 16$.

We know that any non - zero number raised to the power of 1 is itself. So if $16^x = 16$, then $x = 1$ because $16^1=16$.

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