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exercises 1.2 the definite integral
score: 100/170 answered: 10/17
question 11
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\\(\int_{8}^{11} f(x) dx - \int_{8}^{10} f(x) dx = \int_{a}^{b} f(x) dx\\)
where \\(a = \\) and \\(b = \\)
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Step1: Recall integral interval property
For $\int_{c}^{d}f(x)dx - \int_{c}^{e}f(x)dx = \int_{e}^{d}f(x)dx$ when $e Here $c=8$, $d=11$, $e=10$. So $\int_{8}^{11}f(x)dx - \int_{8}^{10}f(x)dx = \int_{10}^{11}f(x)dx$.Step2: Match to given integral
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$a=10$ and $b=11$