Question

expand the logarithm. assume all expressions exist
write your answer as a sum or difference of base - 9 logarithms. the inside of each logarithm must be a(log_{9}vu)

Explanation:

Step1: Recall the product rule of logarithms

The product rule of logarithms states that \(\log_b(MN)=\log_b M+\log_b N\) for any positive real numbers \(b\), \(M\), and \(N\) with \(b
eq1\).

Step2: Apply the product rule to \(\log_9(vu)\)

Here, \(b = 9\), \(M = v\), and \(N = u\). Using the product rule, we get \(\log_9(vu)=\log_9 v+\log_9 u\).

Answer:

\(\log_{9} v + \log_{9} u\)