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3. explain and show why ch₃f is a polar molecule, while cf₄ is not. ove…

Question

  1. explain and show why ch₃f is a polar molecule, while cf₄ is not.

overall
expectations: c2 and c3
not yet
level 4+
100%
demonstrates the concept of vsepr and polarity with a high degree of effectiveness and accuracy.

  • use of correct chemistry terminology
  • clear and detailed diagrams/writing
  • no errors in solution
  • correct and justified conclusion

level 4+
95%
demonstrates the concept of vsepr and polarity, with a high degree of effectiveness and accuracy.

  • use of correct chemistry terminology
  • clear and detailed diagrams/writing
  • correct conclusion
  • slight error in solution

level 4-
85%
demonstrates the concept of vsepr and polarity, with a high degree of effectiveness and accuracy.

  • use of correct chemistry terminology
  • mostly clear and detailed writing/diagrams
  • missing one part of q
  • minor error in solution
  • mostly correct conclusion

level 3
75%
demonstrates the concept of vsepr and polarity, with considerable effectiveness and accuracy.

  • use of correct chemistry terminology
  • considerable detailed writing/diagrams
  • minor errors in solution
  • conclusion not justified

level 2
65%
demonstrates the concept of vsepr and polarity, with some effectiveness and accuracy.

  • some use of correct chemistry terminology
  • some detailed writing/diagrams
  • missing more than one part of the q
  • few errors in solution

level 1
55%
demonstrates the concept of vsepr and polarity, with limited effectiveness and accuracy.

  • limited use of correct chemistry terminology
  • major errors in solution
  • showed something conceptually related to q

Explanation:

Step1: Analyze VSEPR and bonding in CH₃F

In CH₃F, carbon is the central atom. It has four electron - groups (3 C - H bonds and 1 C - F bond) according to VSEPR. The C - F bond is highly polar due to the large electronegativity difference between C (2.5) and F (4.0). The bond dipoles do not cancel out, resulting in a net dipole moment, making CH₃F a polar molecule.

Step2: Analyze VSEPR and bonding in CF₄

In CF₄, carbon is the central atom with four electron - groups (4 C - F bonds). It has a tetrahedral geometry. Although each C - F bond is polar, the symmetry of the tetrahedral shape causes the bond dipoles to cancel each other out. So, the net dipole moment is zero, and CF₄ is a non - polar molecule.

Answer:

CH₃F is polar because the bond dipoles do not cancel out due to its non - symmetric structure with a highly polar C - F bond. CF₄ is non - polar as the symmetric tetrahedral arrangement of the four polar C - F bonds causes the bond dipoles to cancel, resulting in a net dipole moment of zero.