Question

express cos a as a fraction in simplest terms.
right triangle abc with right angle at b, ab = 48, bc = 14, ac = 50

Explanation:

Step1: Recall cosine definition

In a right triangle, $\cos A = \frac{\text{adjacent to } A}{\text{hypotenuse}}$.

Step2: Identify sides

Adjacent to $A$ is $AB = 48$, hypotenuse is $AC = 50$.

Step3: Compute $\cos A$

$\cos A = \frac{48}{50} = \frac{24}{25}$ (simplify by dividing numerator and denominator by 2).

Answer:

$\frac{24}{25}$