QUESTION IMAGE
Question
express (sin g) as a fraction in simplest terms.
Step1: Identify the right triangle sides
In right triangle \( \triangle GHI \) with right angle at \( H \), \( GI = 20 \) (hypotenuse), \( GH = 16 \) (one leg), we first find \( HI \) using Pythagoras: \( HI=\sqrt{GI^{2}-GH^{2}}=\sqrt{20^{2}-16^{2}}=\sqrt{400 - 256}=\sqrt{144}=12 \).
Step2: Recall sine definition
Sine of an angle in a right triangle is \( \sin\theta=\frac{\text{opposite}}{\text{hypotenuse}} \). For \( \angle G \), opposite side is \( HI = 12 \), hypotenuse is \( GI = 20 \).
Step3: Simplify the fraction
\( \sin G=\frac{12}{20}=\frac{3}{5} \) (dividing numerator and denominator by 4).
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\( \frac{3}{5} \)