Question

express the trig ratios as fractions in simplest terms.
answer attempt 1 out of 8
sin k =
cos l =
sin k and cos l .

Explanation:

Step1: Recall sine definition

For angle $K$, $\sin K = \frac{\text{opposite}}{\text{hypotenuse}}$
$\sin K = \frac{JL}{LK} = \frac{\sqrt{31}}{16}$

Step2: Recall cosine definition

For angle $L$, $\cos L = \frac{\text{adjacent}}{\text{hypotenuse}}$
$\cos L = \frac{JL}{LK} = \frac{\sqrt{31}}{16}$

Step3: Compare the two values

Both ratios simplify to the same fraction, so they are equal.

Answer:

$\sin K = \frac{\sqrt{31}}{16}$
$\cos L = \frac{\sqrt{31}}{16}$
$\sin K$ and $\cos L$ are equal