Question

factor 27y - 63z. write your answer as a product with a whole number greater than 1.

Explanation:

Step1: Find the GCF of 27 and 63

The factors of 27 are \(1, 3, 9, 27\). The factors of 63 are \(1, 3, 7, 9, 21, 63\). The greatest common factor (GCF) of 27 and 63 is 9.

Step2: Factor out the GCF

Using the distributive property \(ab - ac = a(b - c)\), where \(a = 9\), \(b = 3y\) (since \(27y\div9 = 3y\)), and \(c = 7z\) (since \(63z\div9 = 7z\)). So, \(27y - 63z = 9(3y - 7z)\).

Answer:

\(9(3y - 7z)\)