Question

factor completely.\\(4f^{3} + 4f^{2} + 7f + 7\\)

Explanation:

Step1: Group terms

Group the first two terms and the last two terms: $(4f^3 + 4f^2) + (7f + 7)$

Step2: Factor out GCF from each group

Factor out $4f^2$ from the first group and $7$ from the second group: $4f^2(f + 1) + 7(f + 1)$

Step3: Factor out common binomial factor

Factor out $(f + 1)$ from the expression: $(4f^2 + 7)(f + 1)$

Answer:

$(4f^2 + 7)(f + 1)$