Question

factor completely.
$-7y^{2}-18y + 9$

Explanation:

Step1: Factor out -1

$-(7y^2 + 18y - 9)$

Step2: Split middle term of quadratic

$7y^2 + 21y - 3y - 9$

Step3: Group and factor pairs

$7y(y + 3) - 3(y + 3)$

Step4: Factor out common binomial

$(7y - 3)(y + 3)$

Step5: Reattach the negative sign

$-1 \times (7y - 3)(y + 3)$

Answer:

$-(7y - 3)(y + 3)$ or $(-7y + 3)(y + 3)$ or $(7y - 3)(-y - 3)$