Question

factor completely.
4k² + 4k + 1

Explanation:

Step1: Identify the form

The expression $4k^{2}+4k + 1$ is in the form of $a^{2}+2ab + b^{2}$, where $a = 2k$ and $b=1$. Since $(a + b)^{2}=a^{2}+2ab + b^{2}$.

Step2: Factor the expression

Substitute $a = 2k$ and $b = 1$ into the perfect - square formula. We get $(2k + 1)^{2}$.

Answer:

$(2k + 1)^{2}$