QUESTION IMAGE
Question
factor completely.
①
$10x^2 + 100x + 250$
②
$3x^2 - 24x + 48$
③
$9x^2 + 30x + 25$
④
$98x^2 + 84x + 18$
Problem 1: \(10x^2 + 100x + 250\)
Step1: Factor out the GCF
First, find the greatest common factor (GCF) of \(10x^2\), \(100x\), and \(250\). The GCF of 10, 100, and 250 is 10.
\(10x^2 + 100x + 250 = 10(x^2 + 10x + 25)\)
Step2: Factor the quadratic
The quadratic \(x^2 + 10x + 25\) is a perfect square trinomial, since \(x^2=(x)^2\), \(25 = 5^2\), and \(10x = 2 \cdot x \cdot 5\). So, \(x^2 + 10x + 25=(x + 5)^2\).
Step1: Factor out the GCF
The GCF of \(3x^2\), \(-24x\), and \(48\) is 3.
\(3x^2 - 24x + 48 = 3(x^2 - 8x + 16)\)
Step2: Factor the quadratic
The quadratic \(x^2 - 8x + 16\) is a perfect square trinomial, since \(x^2=(x)^2\), \(16 = 4^2\), and \(-8x=-2\cdot x\cdot4\). So, \(x^2 - 8x + 16=(x - 4)^2\).
Step1: Identify the perfect square terms
We have \(9x^2=(3x)^2\) and \(25 = 5^2\).
Step2: Check the middle term
The middle term is \(30x\), and \(2\cdot3x\cdot5 = 30x\), which matches the middle term of the trinomial. So, this is a perfect square trinomial.
\(9x^2 + 30x + 25=(3x + 5)^2\)
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\(10(x + 5)^2\)