Question

factor by grouping.\\(2y^{3} + 5y^{2} + 6y + 15\\)

Explanation:

Step1: Group terms into pairs

$(2y^3 + 5y^2) + (6y + 15)$

Step2: Factor out GCF from each pair

$y^2(2y + 5) + 3(2y + 5)$

Step3: Factor out common binomial

$(2y + 5)(y^2 + 3)$

Answer:

$(2y + 5)(y^2 + 3)$