Question

factor by grouping.
\\(10y^3 - 12y^2 + 15y - 18\\)

Explanation:

Step1: Group terms into pairs

$(10y^3 - 12y^2) + (15y - 18)$

Step2: Factor out GCF from each pair

$2y^2(5y - 6) + 3(5y - 6)$

Step3: Factor out common binomial

$(5y - 6)(2y^2 + 3)$

Answer:

$\boldsymbol{(5y - 6)(2y^2 + 3)}$