Question

factor by grouping. 4ns + 7n + 4ps + 7p

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: \((4ns + 7n)+(4ps + 7p)\)

Step2: Factor out the GCF from each group

Factor out \(n\) from the first group and \(p\) from the second group: \(n(4s + 7)+p(4s + 7)\)

Step3: Factor out the common binomial factor

Factor out \((4s + 7)\) from both terms: \((4s + 7)(n + p)\)

Answer:

\((4s + 7)(n + p)\)