Question

for the few questions in this set, you will see the quadratic formula. soon, you will need to answer the questions without this reminder.
$x = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a }$
for $ax^2 + bx + c = 0$

solve for x. write both solutions, separated by a comma.
$6x^2 - x - 5 = 0$
enter the correct answer.

Explanation:

Step1: Identify a, b, c values

From $6x^2 - x - 5 = 0$, we get $a=6$, $b=-1$, $c=-5$.

Step2: Calculate discriminant

$\sqrt{b^2 - 4ac} = \sqrt{(-1)^2 - 4(6)(-5)} = \sqrt{1 + 120} = \sqrt{121} = 11$

Step3: Apply quadratic formula

First solution: $x = \frac{-(-1) + 11}{2(6)} = \frac{12}{12} = 1$
Second solution: $x = \frac{-(-1) - 11}{2(6)} = \frac{-10}{12} = -\frac{5}{6}$

Answer:

$1, -\frac{5}{6}$