Question

fh bisects ∠efg. find the indicated angle measures. m∠gfh = 71 °. find m∠efh and m∠efg. m∠efh = ° m∠efg = °

Explanation:

Step1: Recall angle - bisector property

If a ray bisects an angle, it divides the angle into two equal - sized angles. Since $FH$ bisects $\angle EFG$, then $\angle EFH=\angle GFH$.

Step2: Find $m\angle EFH$

Given $m\angle GFH = 71^{\circ}$, and $\angle EFH=\angle GFH$, so $m\angle EFH = 71^{\circ}$.

Step3: Find $m\angle EFG$

Since $\angle EFG=\angle EFH+\angle GFH$ and $\angle EFH=\angle GFH = 71^{\circ}$, then $m\angle EFG=71^{\circ}+71^{\circ}=142^{\circ}$.

Answer:

$m\angle EFH = 71^{\circ}$
$m\angle EFG = 142^{\circ}$