Question

1. in the figure, $jk = 5x + 7$, $kl = 7x + 2$ and $jl = 45$.

6a find x.

Explanation:

Step1: Apply segment addition postulate

Since \( JK + KL = JL \), substitute the given expressions: \( (5x + 7)+(7x + 2)=45 \)

Step2: Combine like terms

Simplify the left - hand side: \( 5x+7x + 7 + 2=45\), which gives \( 12x+9 = 45 \)

Step3: Subtract 9 from both sides

\( 12x+9 - 9=45 - 9\), so \( 12x=36 \)

Step4: Divide both sides by 12

\( \frac{12x}{12}=\frac{36}{12} \), which gives \( x = 3 \)

Answer:

\( x = 3 \)