Question

the figure below is dilated by a factor of 4 centered at the origin. plot the resulting image.
click twice to plot a segment.
click a segment to delete it.

Explanation:

Step1: Identify original coordinates

Original points: $A(0, -3)$, $B(2, 2)$, $C(-2, 1)$

Step2: Apply dilation factor 4

For a dilation centered at the origin, multiply each coordinate by the scale factor 4:

• $A'(0 \times 4, -3 \times 4) = (0, -12)$
• $B'(2 \times 4, 2 \times 4) = (8, 8)$
• $C'(-2 \times 4, 1 \times 4) = (-8, 4)$

Step3: Plot and connect points

Plot $A'(0, -12)$, $B'(8, 8)$, $C'(-8, 4)$, then connect $A'-B'$, $B'-C'$, $C'-A'$.

Answer:

The dilated image has vertices at $(0, -12)$, $(8, 8)$, and $(-8, 4)$. Connect these three points to form the dilated triangle.