Question

in the figure below, m∠wxz = 76°, and m∠2 is three times m∠1. find m∠1.

Explanation:

Step1: Set up an equation

Let $m\angle1 = x$. Then $m\angle2=3x$. Since $m\angle WXZ=m\angle1 + m\angle2$ and $m\angle WXZ = 76^{\circ}$, we have the equation $x + 3x=76^{\circ}$.

Step2: Combine like - terms

Combining the left - hand side of the equation $x + 3x=76^{\circ}$, we get $4x = 76^{\circ}$.

Step3: Solve for $x$

Dividing both sides of the equation $4x = 76^{\circ}$ by 4, we have $x=\frac{76^{\circ}}{4}=19^{\circ}$.

Answer:

$19$