Question

the figure shows the elements of period 3 and the first 3 elements of group 6a of the periodic table. use the figure to answer questions 10 and 11. which list of symbols, in order from left to right, correctly completes the following passage? from the group 6a elements shown in the diagram, the element with the largest atomic radius is __. in period 3, the element with the largest atomic radius is . the three atoms which would form ions which are smaller in size than their parent atoms are al, mg and . in period 3, has the highest ionization energy, while in group 6a __ has the highest ionization energy. o se na cl ar se o se na na ar o o ar cl na se o o ar na na o

Explanation:

1. Atomic radius in Group 6A: Atomic radius increases down a group. Among O, S, and Se in Group 6A, Se has the largest atomic radius as it has more electron - shells.
2. Atomic radius in Period 3: Atomic radius decreases across a period from left to right. So, in Period 3, Na has the largest atomic radius.
3. Ion size compared to parent atom: Metals lose electrons to form cations which are smaller than their parent atoms. Al, Mg, and Na are metals and form smaller - sized cations.
4. Ionization energy in Period 3: Ionization energy generally increases across a period. Ar has the highest ionization energy in Period 3 as it has a stable noble - gas electron configuration.
5. Ionization energy in Group 6A: Ionization energy decreases down a group. O has the highest ionization energy in Group 6A.

Answer:

Se, Na, Na, Ar, O