Question

fill in the blank 2 points
balance the following equation:
1
li+ 1
alcl₃--> 3
licl+ 2
al

Explanation:

Step1: Identify atoms to balance

We have the equation (unbalanced): $ \text{Li} + \text{AlCl}_3
ightarrow \text{LiCl} + \text{Al} $

First, look at Cl atoms. On the left, in $\text{AlCl}_3$, there are 3 Cl. On the right, in $\text{LiCl}$, there is 1 Cl. So we need to put a coefficient of 3 in front of $\text{LiCl}$ to balance Cl: $ \text{Li} + \text{AlCl}_3
ightarrow 3\text{LiCl} + \text{Al} $

Step2: Balance Li atoms

Now, Li on the right is 3 (from $3\text{LiCl}$), so we put 3 in front of Li on the left: $ 3\text{Li} + \text{AlCl}_3
ightarrow 3\text{LiCl} + \text{Al} $

Step3: Balance Al atoms

Al on the left is 1 (from $\text{AlCl}_3$) and on the right is 1 (from $\text{Al}$), so Al is already balanced.

Wait, but the problem's initial blanks: Let's re - express the equation with the given blanks. The equation structure is: $ \underline{1}\text{Li} + \underline{1}\text{AlCl}_3
ightarrow \underline{3}\text{LiCl} + \underline{1}\text{Al} $? No, wait the user's interface has blanks: first blank (Li), second (Al), third (LiCl). Wait, maybe the correct balanced equation is $ 3\text{Li} + \text{AlCl}_3 = 3\text{LiCl} + \text{Al} $. But the given blanks: first blank (Li) has a default 1, second (Al) default 2? Wait, maybe I misread. Let's check the atoms again.

Wait, the original equation in the problem (from the image) is: $ \underline{1}\text{Li} + \underline{2}\text{Al} + \underline{1}\text{AlCl}_3
ightarrow \underline{3}\text{LiCl} +...$ No, no, the correct approach is to balance the equation properly.

The correct balanced chemical equation for the reaction between lithium (Li) and aluminium chloride ($\text{AlCl}_3$) is a single - displacement reaction:

1. Balance Cl: There are 3 Cl in $\text{AlCl}_3$, so we need 3 $\text{LiCl}$ (since each $\text{LiCl}$ has 1 Cl). So put 3 in front of $\text{LiCl}$.
2. Balance Li: Since we have 3 $\text{LiCl}$, we need 3 Li on the left, so put 3 in front of Li.
3. Balance Al: There is 1 Al in $\text{AlCl}_3$ and 1 Al on the right, so Al is balanced.

So the balanced equation is $ 3\text{Li} + \text{AlCl}_3 = 3\text{LiCl} + \text{Al} $

But the given blanks:

• For Li: the first blank (Li) should be 3, but it's given as 1? Wait, maybe the problem's blanks are for the coefficients in the order: Li, Al, $\text{AlCl}_3$, $\text{LiCl}$, Al. Wait, no, the image shows:

First blank: Li (with 1 as default)

Second blank: Al (with 2 as default)

Third blank: $\text{AlCl}_3$ (with 1 as default)

Fourth blank: $\text{LiCl}$ (with 3 as default)

Fifth blank: Al (?)

Wait, maybe the correct coefficients are:

Li: 3, Al: 1, $\text{AlCl}_3$: 1, $\text{LiCl}$: 3, Al: 1.

But the user's blanks:

First blank (Li): should be 3 (but given 1, maybe a mistake, but following the balancing steps, the coefficient for Li is 3, for Al is 1, for $\text{LiCl}$ is 3.

But the problem's interface has:

1 (Li) + 2 (Al) + 1 ($\text{AlCl}_3$) -> 3 ($\text{LiCl}$) +...

Wait, no, the correct balanced equation is $ 3\text{Li} + \text{AlCl}_3 = 3\text{LiCl} + \text{Al} $. So the coefficients are: Li: 3, $\text{AlCl}_3$: 1, $\text{LiCl}$: 3, Al: 1.

If we consider the blanks:

• Coefficient of Li: 3
• Coefficient of Al: 1
• Coefficient of $\text{LiCl}$: 3

But the given blanks: first (Li) has 1, second (Al) has 2, third ($\text{LiCl}$) has 3. Maybe there was a mis - formatting. But following the balancing rules:

Answer:

The balanced equation is $ \boldsymbol{3}\text{Li} + \text{AlCl}_3 = 3\text{LiCl} + \text{Al} $, so the coefficients (for the blanks in order: Li, Al, LiCl) should be 3, 1, 3. But if we follow the given blank structure (with first Li as 1, second Al as 2, third LiCl as 3), there might be a mistake, but the correct balanced coefficients are 3 (Li), 1 (Al), 3 (LiCl).