Question

fill in the blank question
a 10-kg box is attached to two strings, each on opposite ends of the box. the string on the right is pulled to the right with a 6 n force while the left string is pulled to the left with 6 n. due to these pulls, the box experiences an acceleration of ____ m/s² to the left (take the left direction to be positive).

Explanation:

Step1: Define net force

Let left be positive. Left force $F_1=6\ \text{N}$, right force $F_2=-6\ \text{N}$.
Net force: $F_{net}=F_1+F_2=6 + (-6)=0\ \text{N}$

Step2: Apply Newton's second law

Newton's second law: $F_{net}=ma$, so $a=\frac{F_{net}}{m}$
Substitute $F_{net}=0\ \text{N}$, $m=10\ \text{kg}$:
$a=\frac{0}{10}=0\ \text{m/s}^2$

Answer:

$0$