Question

fill in the blanks with the terms provided. not all terms will be used.

1. if $hp_b$ is 16 mm hg, $cop_b$ is 26 mm hg, $cop_{if}$ is 5 mm hg, and $hp_{if}$ is 0 mm hg at the venous end of a capillary, calculate the net filtration pressure.
2. ( (click to select) mm hg - (click to select) mm hg ) - ( (click to select) mm hg - (click to select) mm hg ) = (click to select)

options: 10, 15, 16, 0, 26, 5, -5

Explanation:

Step1: Recall net - filtration pressure formula

The formula for net filtration pressure (NFP) at the venous end of a capillary is $NFP=(HP_b - COP_b)-(HP_{if}-COP_{if})$, where $HP_b$ is hydrostatic pressure in blood, $COP_b$ is colloid osmotic pressure in blood, $HP_{if}$ is hydrostatic pressure in interstitial fluid, and $COP_{if}$ is colloid osmotic pressure in interstitial fluid.

Step2: Substitute given values

Given $HP_b = 16$ mm Hg, $COP_b=26$ mm Hg, $HP_{if}=0$ mm Hg, and $COP_{if}=5$ mm Hg.
Substitute into the formula: $(16 - 26)-(0 - 5)$.
First, calculate $16−26=- 10$ and $0 - 5=-5$.
Then, $(-10)-(-5)=-10 + 5=-5$ mm Hg.

Answer:

-5