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Question
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mole of zinc contains 6.022x10^23 atoms of zinc.
mole of silver contains 3.011x10^23 atoms of silver.
Step1: Recall Avogadro's number
One mole of any substance contains $6.022\times 10^{23}$ entities (atoms, molecules etc.). So for zinc, 1 mole of zinc contains $6.022\times 10^{23}$ atoms of zinc.
Step2: Calculate moles of silver
We know that the number of moles $n=\frac{N}{N_A}$, where $N$ is the number of atoms and $N_A = 6.022\times 10^{23}\text{ atoms/mol}$. Given $N = 3.011\times 10^{23}$ atoms of silver. Then $n=\frac{3.011\times 10^{23}}{6.022\times 10^{23}} = 0.5$ moles.
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