Question

fill in the table using this function rule.
$y = -3x + 5$

$x$	$y$
$-1$	$square$
$0$	$square$
$1$	$square$

Explanation:

Step1: Substitute \( x = -2 \) into \( y = -3x + 5 \)

\( y = -3\times(-2) + 5 = 6 + 5 = 11 \)

Step2: Substitute \( x = -1 \) into \( y = -3x + 5 \)

\( y = -3\times(-1) + 5 = 3 + 5 = 8 \)

Step3: Substitute \( x = 0 \) into \( y = -3x + 5 \)

\( y = -3\times0 + 5 = 0 + 5 = 5 \)

Step4: Substitute \( x = 1 \) into \( y = -3x + 5 \)

\( y = -3\times1 + 5 = -3 + 5 = 2 \)

Answer:

When \( x = -2 \), \( y = 11 \); when \( x = -1 \), \( y = 8 \); when \( x = 0 \), \( y = 5 \); when \( x = 1 \), \( y = 2 \)

So the completed table is:

\( x \)	\( y \)
\( -1 \)	\( 8 \)
\( 0 \)	\( 5 \)
\( 1 \)	\( 2 \)