Question

find the $x$-intercept and $y$-intercept of the line.
$2x + 4y = -12$
$x$-intercept: $square$
$y$-intercept: $square$

Explanation:

Step1: Find x-intercept, set $y=0$

Substitute $y=0$ into $2x+4y=-12$:
$2x + 4(0) = -12$

Step2: Solve for $x$

$2x = -12$
$x = \frac{-12}{2} = -6$

Step3: Find y-intercept, set $x=0$

Substitute $x=0$ into $2x+4y=-12$:
$2(0) + 4y = -12$

Step4: Solve for $y$

$4y = -12$
$y = \frac{-12}{4} = -3$

Answer:

x -intercept: $-6$
y -intercept: $-3$