Question

$f(x)=3x + 5$; find $f(-3)$

1. $f(x)=-x^2 - 4x + 1$;

Explanation:

Step1: Substitute $x=-3$ into $f(x)$

$f(-3)=3(-3)+5$

Step2: Calculate the multiplication

$f(-3)=-9+5$

Step3: Calculate the final sum

$f(-3)=-4$

Answer:

$-4$

Note: The second function $f(x)=-x^2-4x+1$ is incomplete (the value to evaluate is missing), so only the solution for $f(x)=3x+5; \text{Find }f(-3)$ is provided. If you provide the full question for the second function, I can assist with that as well.