find y if y = \\frac{2}{3x^{3}}. y = □

$find y if y = \\frac{2}{3x^{3}}. y = □$

find y if y = \frac{2}{3x^{3}}. y = □

Rewrite $y = \frac{2}{3x^{3}}$ as $y=\frac{2}{3}x^{- 3}$.

The power - rule states that if $y = ax^{n}$, then $y'=anx^{n - 1}$. Here, $a=\frac{2}{3}$ and $n=-3$. So, $y'=\frac{2}{3}\times(-3)x^{-3 - 1}$.

$y'=- 2x^{-4}=-\frac{2}{x^{4}}$.

$-\frac{2}{x^{4}}$