Question

find the 49th term of this arithmetic sequence. -15, -10, -5, 0, 5, ... a_{49} = ? hint: a_n = a_1 + (n - 1)d

Explanation:

Step1: Identify known values

$a_1 = -15$, $n = 49$, $d = -10 - (-15) = 5$

Step2: Substitute into arithmetic formula

$a_{49} = -15 + (49 - 1) \times 5$

Step3: Simplify the expression

$a_{49} = -15 + 48 \times 5 = -15 + 240$

Step4: Calculate final value

$a_{49} = 225$

Answer:

225