Question

find the 98th term of the arithmetic sequence -10, -8, -6, ...

Explanation:

Step1: Identify first - term and common - difference

The first term $a_1=-10$, and the common difference $d=-8 - (-10)=2$.

Step2: Use the formula for the nth term of an arithmetic sequence

The formula for the $n$th term of an arithmetic sequence is $a_n=a_1+(n - 1)d$. Substitute $n = 98$, $a_1=-10$, and $d = 2$ into the formula:
$a_{98}=-10+(98 - 1)\times2$.

Step3: Simplify the expression

First, calculate $98−1 = 97$. Then, $97\times2=194$. Finally, $a_{98}=-10 + 194$.
$a_{98}=184$.

Answer:

$184$