QUESTION IMAGE
Question
- find the area of each triangle. explain or show your reasoning.
a.
b.
- a student said, \we cant find the area of the shaded region beca shape has many different measurements, instead of just a length width that we could multiply.\
Part a: Area of the Triangle
Step1: Identify base and height
Assume each grid square has side length 1. The base of the triangle spans 4 units, and the height spans 4 units (by counting grid squares).
Step2: Apply triangle area formula
The formula for the area of a triangle is $A = \frac{1}{2} \times \text{base} \times \text{height}$. Substituting base = 4 and height = 4:
$A = \frac{1}{2} \times 4 \times 4$
Step3: Calculate the area
$\frac{1}{2} \times 4 \times 4 = 8$
Part b: Area of the Triangle
Step1: Identify base and height
Assume each grid square has side length 1. The base of the triangle spans 4 units, and the height spans 3 units (by counting grid squares).
Step2: Apply triangle area formula
Using $A = \frac{1}{2} \times \text{base} \times \text{height}$, substitute base = 4 and height = 3:
$A = \frac{1}{2} \times 4 \times 3$
Step3: Calculate the area
$\frac{1}{2} \times 4 \times 3 = 6$
Part 5: Area of the Shaded Region
Step1: Decompose the shape
The shaded region can be divided into three rectangles:
- Left rectangle: $10 \times 10$
- Middle rectangle: $35 \times (10 + 10)$ (height is $10 + 10$)
- Right rectangle: $15 \times 10$ (wait, correction: total width is 65, so middle width is $65 - 10 - 15 = 40$? Wait, re-examine:
Wait, the bottom rectangle has width 65 and height 10 (from bottom to 10). Then the middle top rectangle has width 35 and height 10 (from 10 to 20). The left small rectangle: width 10, height 10 (from 10 to 20, left of middle).
Wait, better decomposition:
- Bottom rectangle: width 65, height 10: $65 \times 10$
- Middle rectangle: width 35, height 10: $35 \times 10$
- Left rectangle: width 10, height 10: $10 \times 10$
Wait, no—let’s use the given dimensions:
Total height: 30 (from bottom to top). The bottom part: height 10 (since 30 - 20 = 10? Wait, the diagram shows 30 total height, with a 10-unit step and a 10-unit step. Let’s re-express:
- Bottom rectangle: width 65, height 10 (area: $65 \times 10$)
- Middle rectangle: width 35, height 10 (area: $35 \times 10$)
- Left rectangle: width 10, height 10 (area: $10 \times 10$)
Wait, but 10 + 35 + 15 = 60? No, 10 + 35 + 20? Wait, the total width is 65. Let’s check:
Left: 10, Middle: 35, Right: 15? 10 + 35 + 15 = 60, not 65. Maybe the bottom width is 65, height 10. Then the middle (top of bottom) has width 35 + 10 = 45? No, this is confusing. Alternatively, use the student’s mistake: the shape can be decomposed into rectangles.
Correct decomposition:
- Bottom rectangle: width 65, height 10: $65 \times 10 = 650$
- Middle rectangle: width 35, height 10: $35 \times 10 = 350$
- Left rectangle: width 10, height 10: $10 \times 10 = 100$
Total area: $650 + 350 + 100 = 1100$? Wait, no—wait, the left rectangle is 10x10, middle is 35x(10+10) [height 20?], and right is 15x10? No, the total height is 30. Let’s do:
Height of bottom part: 10 (from y=0 to y=10)
Height of middle part: 10 (from y=10 to y=20)
Height of top part: 10 (from y=20 to y=30)? No, the diagram shows 30 total, with a 10-unit step and a 10-unit step. Let’s use the given numbers: 10, 35, 10, 15, 30.
Alternative approach: The shaded region is a composite of three rectangles:
- Left: $10 \times 10$ (width 10, height 10)
- Middle: $35 \times (10 + 10)$ (width 35, height 20)
- Right: $15 \times 10$ (width 15, height 10)
Wait, 10 + 35 + 15 = 60, but total width is 65. Maybe the bottom width is 65, height 10 (area $65 \times 10$), then the middle (above bottom) has width 35 + 10 = 45? No, this is unclear. Wait, the student’s diagram: total width 65, height 30. The shaded area has:
- A bottom rectangle: width 65, height 10 (area $65 \times 10 = 650$)
- A middle rectangle: width 35, height 10 (area $35 \times 10 = 350$)
- A left rectangle: width 10, height 10 (area $10 \times 10 = 100$)
Total area: $650 + 350 + 100 = 1100$? Wait, but 10 + 35 + 20 = 65? Maybe the right part is 20, not 15. The handwritten “15+20” suggests 15 and 20. So 10 (left) + 35 (middle) + 20 (right) = 65. Then:
- Bottom: 65 x 10 = 650
- Middle: 35 x 10 = 350 (height 10, from 10 to 20)
- Left: 10 x 10 = 100 (height 10, from 10 to 20, left of middle)
- Right: 20 x 10 = 200? No, this is overcomplicating. The key is that the student is wrong—we can decompose the shape into rectangles and sum their areas.
But since the problem is to find the area (and the student says it’s impossible), we show decomposition:
Step1: Decompose into rectangles
- Rectangle 1: Width 10, Height 10 (left small)
- Rectangle 2: Width 35, Height 20 (middle, spanning two 10-unit heights…
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s:
a. $\boldsymbol{8}$ (units²)
b. $\boldsymbol{6}$ (units²)
- The area can be found by decomposing the shape into rectangles (e.g., bottom: $65 \times 10$, middle: $35 \times 10$, left: $10 \times 10$, right: $15 \times 10$—wait, no, correct total area calculation:
Wait, let’s use the given dimensions:
- Left rectangle: $10 \times 10 = 100$
- Middle rectangle: $35 \times (10 + 10) = 35 \times 20 = 700$
- Right rectangle: $15 \times 10 = 150$
Total area: $100 + 700 + 150 = 950$ (units²)
(Note: The exact decomposition depends on the diagram’s details, but the key is that decomposition works.)