Question

find the area of a trapezoid with a base of 28 ft, a height of 20 ft, and top of 12 ft.

Explanation:

Step1: Recall area formula

$A=\frac{1}{2}(b_1 + b_2)h$, where $b_1,b_2$ are bases and $h$ is height.

Step2: Identify values

$b_1 = 12$, $b_2=28$, $h = 20$.

Step3: Substitute values

$A=\frac{1}{2}(12 + 28)\times20$.

Step4: Simplify

First, $12+28 = 40$. Then $\frac{1}{2}\times40\times20=400$.

Answer:

$400$