Question

find the areas of the trapezoids. a = 6 cm² b1 = 4 cm a = a = a = __

Explanation:

Step1: Recall trapezoid - area formula

The formula for the area of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the lengths of the parallel - sides and $h$ is the height.

First trapezoid:

Given $b_1 = 4$ mm, $b_2=7$ mm, and $h = 2$ mm.

Step2: Substitute values into formula

$A=\frac{(4 + 7)\times2}{2}$
$=\frac{11\times2}{2}$
$=11$ mm²

Second trapezoid:

Given $b_1 = 9$ m, $b_2 = 5$ m, and $h = 6$ m.

Step3: Substitute values into formula

$A=\frac{(9 + 5)\times6}{2}$
$=\frac{14\times6}{2}$
$=42$ m²

Third trapezoid (assuming it's a trapezoid with $b_1$ and $b_2$ as parallel - sides and $h$ as height):

Given $b_1$ (longer side) $=8$ km, $b_2$ (shorter side) $=2$ km, assume height $h$ (not clearly marked but if we consider the perpendicular distance between parallel sides). Let's assume the height is the perpendicular distance between the two parallel - looking sides. If we assume the height is the vertical distance, and using the trapezoid area formula.

Step4: Substitute values into formula

$A=\frac{(8 + 2)\times h}{2}$ (assuming $h$ is the perpendicular distance between parallel sides. If we assume $h$ is the vertical distance shown as 2 km)
$A=\frac{(8 + 2)\times2}{2}=10$ km²

Answer:

11 mm²
42 m²
10 km²