Question

find the binomial that completes the factorization.
$y^{3}+z^{3}=\left(\square\
ight)\left(y^{2}-yz+z^{2}\
ight)$

Explanation:

Step1: Recall sum of cubes formula

The sum of cubes identity is $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$

Step2: Match given terms to formula

Here, $a = y$ and $b = z$. Compare $y^3 + z^3$ to $a^3 + b^3$, so the missing binomial is $a + b$.

Answer:

$y + z$