Question

find the center and radius of the circle. write the standard form of the equation.
the center of the circle is (3.5, (type an ordered pair.)

Explanation:

1. Recall the standard - form of the equation of a circle:

• The standard form of the equation of a circle is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center of the circle and \(r\) is the radius.
• Given that the center of the circle is \((3,5)\) (assuming the value in the box is a mis - type and should be \((3,5)\) as an ordered pair).

1. Let's assume we need to find the standard - form equation with an unknown radius \(r\):

• Substitute \(h = 3\) and \(k = 5\) into the standard - form equation.
• The standard form of the equation of the circle is \((x - 3)^2+(y - 5)^2=r^2\). Since the radius is not given in the problem statement, we leave it as \(r\) in the equation.

Answer:

The center of the circle is \((3,5)\) and the standard form of the equation of the circle is \((x - 3)^2+(y - 5)^2=r^2\)