Question

find class boundaries, midpoint, and width for the class.
42 - 46
part: 0 / 3
part 1 of 3
the class boundaries for the class are 11.5 - 46.5.

Explanation:

Step1: Find lower class boundary

To find the lower class boundary, we take the lower limit of the class (42) and subtract 0.5. So, $42 - 0.5 = 41.5$.

Step2: Find upper class boundary

To find the upper class boundary, we take the upper limit of the class (46) and add 0.5. So, $46 + 0.5 = 46.5$.

Step3: Find midpoint

The formula for the midpoint of a class is $\frac{\text{Lower limit} + \text{Upper limit}}{2}$. Substituting the values, we get $\frac{42 + 46}{2} = \frac{88}{2} = 44$.

Step4: Find class width

The class width is the difference between the upper class boundary and the lower class boundary. So, $46.5 - 41.5 = 5$.

Answer:

• Class boundaries: $41.5 - 46.5$
• Midpoint: $44$
• Class width: $5$