Question

find the % composition of n and h in nh₃
n blank / blank × 100 = blank
h blank / blank × 100 = blank
= 14.007 g/mol ≈ 3.024 g/mol ≈ 17.031 g/mol ≈ 82.24 % ≈ 17.76 % ≈ 14.007 %
≈ 3.024 %

Explanation:

Step1: Calculate % composition of N

The molar mass of N in \(NH_3\) is \(14.007\) g/mol, and the molar mass of \(NH_3\) is \(17.031\) g/mol. The formula for % composition is \(\frac{\text{Molar mass of element in compound}}{\text{Molar mass of compound}} \times 100\). For N: \(\frac{14.007}{17.031} \times 100\)
\[
\frac{14.007}{17.031} \times 100 \approx 82.24\%
\]

Step2: Calculate % composition of H

The molar mass of H in \(NH_3\) (3 H atoms, each 1.008 g/mol, so \(3\times1.008 = 3.024\) g/mol) and the molar mass of \(NH_3\) is \(17.031\) g/mol. For H: \(\frac{3.024}{17.031} \times 100\)
\[
\frac{3.024}{17.031} \times 100 \approx 17.76\%
\]

Answer:

For N: \(\frac{14.007\ \text{g/mol}}{17.031\ \text{g/mol}} \times 100 = 82.24\%\)
For H: \(\frac{3.024\ \text{g/mol}}{17.031\ \text{g/mol}} \times 100 = 17.76\%\)