Question

5 find the discriminant of each quadratic equation then state the number and type of solutions. \\(-3x^2 - 6x - 3 = 0\\) the discriminant is \\(\boxed{}\\), and there is/are \\(\boxed{}\\) \\(\boxed{}\\) solution(s).

Explanation:

Step1: Identify quadratic coefficients

For $-3x^2 -6x -3=0$, $a=-3$, $b=-6$, $c=-3$

Step2: Apply discriminant formula

Discriminant: $\Delta = b^2 - 4ac$
$\Delta = (-6)^2 - 4(-3)(-3)$

Step3: Calculate discriminant value

$\Delta = 36 - 36 = 0$

Step4: Classify solutions

When $\Delta=0$, there is 1 real repeated solution.

Answer:

The discriminant is $0$, and there is/are 1 real repeated solution(s).